2x^2+(k+1)x+8=0

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Solution for 2x^2+(k+1)x+8=0 equation:


Simplifying
2x2 + (k + 1) * x + 8 = 0

Reorder the terms:
2x2 + (1 + k) * x + 8 = 0

Reorder the terms for easier multiplication:
2x2 + x(1 + k) + 8 = 0
2x2 + (1 * x + k * x) + 8 = 0

Reorder the terms:
2x2 + (kx + 1x) + 8 = 0
2x2 + (kx + 1x) + 8 = 0

Reorder the terms:
8 + kx + 1x + 2x2 = 0

Solving
8 + kx + 1x + 2x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + kx + 1x + -8 + 2x2 = 0 + -8

Reorder the terms:
8 + -8 + kx + 1x + 2x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + kx + 1x + 2x2 = 0 + -8
kx + 1x + 2x2 = 0 + -8

Combine like terms: 0 + -8 = -8
kx + 1x + 2x2 = -8

Add '-1x' to each side of the equation.
kx + 1x + -1x + 2x2 = -8 + -1x

Combine like terms: 1x + -1x = 0
kx + 0 + 2x2 = -8 + -1x
kx + 2x2 = -8 + -1x

Add '-2x2' to each side of the equation.
kx + 2x2 + -2x2 = -8 + -1x + -2x2

Combine like terms: 2x2 + -2x2 = 0
kx + 0 = -8 + -1x + -2x2
kx = -8 + -1x + -2x2

Divide each side by 'x'.
k = -8x-1 + -1 + -2x

Simplifying
k = -8x-1 + -1 + -2x

Reorder the terms:
k = -1 + -8x-1 + -2x

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